flipside

    pyth_contracts_count_bsc
    Cipher009-CpUJ5kpyth_contracts_count_bsc
    Updated 2024-06-26
    select 'bsc' as chain, count(distinct from_address) as pyth_bsc_contracts_count
    from bsc.core.fact_traces
    where to_address = lower('0x4D7E825F80BDF85E913E0DD2A2D54927E9DE1594') and tx_status = 'SUCCESS';

    QueryRunArchived: QueryRun has been archived