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pyth_contracts_count_polygon
Cipher009-CpUJ5k
pyth_contracts_count_polygon
Updated 2024-06-26
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›
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select
'polygon'
as
chain
,
count
(
distinct
from_address
)
as
pyth_polygon_contracts_count
from
polygon
.
core
.
fact_traces
where
to_address
=
lower
(
'0xff1a0f4744e8582DF1aE09D5611b887B6a12925C'
)
and
tx_status
=
'SUCCESS'
;
Results
QueryRunArchived: QueryRun has been archived