Cipher009-CpUJ5kpyth_contracts_count_polygon
    Updated 2024-06-26
    select 'polygon' as chain, count(distinct from_address) as pyth_polygon_contracts_count
    from polygon.core.fact_traces
    where to_address = lower('0xff1a0f4744e8582DF1aE09D5611b887B6a12925C') and tx_status = 'SUCCESS';